Ayudaaaa urgente [tex] \frac{6x – 2 }{4} – \frac{3}{2 } = \frac{x + 2}{4} – \frac{1}{4} [/tex] a. 3 b. 1 c.4

Ayudaaaa urgente
[tex] \frac{6x – 2 }{4} – \frac{3}{2 } = \frac{x + 2}{4} – \frac{1}{4} [/tex]
a. 3
b. 1
c.4
d.5
e.6​

1 comentario en «Ayudaaaa urgente [tex] \frac{6x – 2 }{4} – \frac{3}{2 } = \frac{x + 2}{4} – \frac{1}{4} [/tex] a. 3 b. 1 c.4<br»

  1. 2(6x-2) – 12 / 8. = 4(x+2) – 4
    12x – 4 – 12 / 8 = 4x + 8 – 4 / 4
    12x – 16 / 8 = 4x + 4 / 4
    4(12x – 16) = 8(4x+4)
    48x – 64 = 32x + 32
    48x – 32x = 32 + 64
    16x = 96
    X = 96/16
    X = 48/8
    X = 24/4
    X = 12/2
    X = 6

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