[tex] \frac{5 }{6} x {}^{2} + \frac{1}{2} = \frac{17}{10} [/tex] ​

[tex] \frac{5 }{6} x {}^{2} + \frac{1}{2} = \frac{17}{10} [/tex]

1 comentario en «[tex] \frac{5 }{6} x {}^{2} + \frac{1}{2} = \frac{17}{10} [/tex] ​»

  1. ¡Hola!

    [tex] \frac{5}{6} {x}^{2} + \frac{1}{2} = \frac{17}{10} \\ \\ \frac{5}{6} {x}^{2} = \frac{17}{10} – \frac{1}{2} \\ \\ \frac{5}{6} {x}^{2} = \frac{17 – 5}{10} \\ \\ \frac{5}{6} {x}^{2} = \frac{12}{10} \\ \\ 5 {x}^{2} = \frac{6 \times 6}{5} \\ \\ {x}^{2} = \frac{ \frac{36}{5} }{5} \\ \\ {x}^{2} = \frac{36}{5 \times 5} = \frac{36}{25} \\ \\ \sqrt{ {x}^{2} } = \pm \frac{ \sqrt{36} }{ \sqrt{25} } \\ \\ x_{1} = \frac{6}{5} \\ \\ x_{2} = – \frac{6}{5} [/tex]

    Entonces los valores de x son:

    [tex] \big\{x_{1} = \frac{6}{5} \ , \ x_{2} = – \frac{6}{5} \big\}[/tex]

    Espero que sirva y saludos.

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